Adamas lock strength

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nick_30

Joined
Aug 21, 2011
Messages
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I've already made a long post about this in general discussion but I was hoping maybe benchmade could shed some light on the subject.

I am trying to figure out how benchmade came up with their 800lb lock strength claim on the 275 adamas.
From the BM testing video I watched, the lock failed at 1717inlb of force, which is 143ftlb. So how did they get 800lbs from that. Not that I dont believe that but just wondering the dynamics of how they came up with that number.
 
800lbs applied at 2.145 inches from the pivot point is 1,717 in.lbf of torque. The lock must resist the applied torque or it fails.

Force x distance is torque.

What BM hasn't said is the length of the moment arm at which the force was applied. But the basic principle is force times the length of the lever arm.
 
Holy smokes. This is easy.

Force (800 pounds) times distance (2.145 inches) equals 1,717 pound inches (units of torque, or inch pounds)

Torque in inch pounds divided by 12 is the same as torque in foot-pounds, or 1717÷12=143.2

Your math above is mixing up the feet and inches. Benchmade has this right. It IS adding up.
 
1 pound hanging at the end of a 1 foot lever is 1 ft-lb of torque. It is also 12 inch pounds of torque.
 
You know, I will say that there have been a lot of post about how horrible the adamas is at cutting abilities with the very obtuse primary grind angles but I will say I am actually surprised at its cutting ability. The with of the bevel at a 20 degree is not that wide. Having reprofiled a zt560 to 20ﾟthere is a big difference in the with of the secondary bevel which indicates a wider edge thickness behind the edge. I am pretty impressed, by the looks of the grind I was very suspicious of it being able to cut anything well, sure, it's no pm2, but it is a TON more heavy duty than that
 
Haha, just getting caught up here. We usually do the lock breaks at 2 inches from the pivot. Looks like TR got it set straight.
 
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