Becker Mathematics

C

CM_Rick

Joined
Jan 10, 2011
Messages
1,402
I had a 14 and didn't even know it...

29BD7F72-3AB5-46E4-A2F9-9E4DBD988AE7_zpseclwpfud.jpg
[/URL][/IMG]
 
But an actual 4 is in transit. And, btw, that's a 9 & a 5... So I would then have 9.
 
Hmmmm.....if 9 - 5 = 4 then BK9 minus BK5 must equal BK4.

However, referencing the picture... BK9 + BK5 - BK5 would equal BK9.

I see the dilemma. But I usually solve this type of math problem by adding more BKx's to the equation whenever I can.
 
Let's see some more equation models, guys... I can't do the math without seeing all the variables.
 
The only thing I have been able to come up with after too much math was the following:
If you add up all of the Beckers and things to get for them, you get an empty wallet...
 
Dear Math, I am not a psychiatrist, solve your own problems.

The nth degree of owning Beckers is inversely proportional to the amount of lunch money in ones pocket.
 
I'm hoping this math equation works out sometime in the not too distant future:

My wallet - my money + great vendor = BK21

Notice there is no accounting for time in the listed variables so as yet it is just an unsolvable theoretical mathematics equation.
 
mbay1455 said:
I'm hoping this math equation works out sometime in the not too distant future:

My wallet - my money + great vendor = BK21

Notice there is no accounting for time in the listed variables so as yet it is just an unsolvable theoretical mathematics equation.
Click to expand...

No, you just need to use the quadratic equation (ax^2 + bx + c). Then convert your variables for time (t), and you have wt^2 + vt + c. W = wallet, while v = vendor, and c = your money. We can estimate time(t) at roughly 90 days from now. You know your values for w and v.
 
You must log in or register to reply here.
Back
Top