I did some quick math to see if I could actually see how much shealding the carbon could give us. Here is how my thought process went.
1 briquette is 180 grams
CO2 is 44.01 g/mol
1 mol CO2 is 24.465 L
Carbon has an atomic weight of 12.011
Oxygen has an atomic weight of 15.999
Air is an average of 20.95% Oxygen
Oxygen is 64g/mol
Oxygen is 22.4L/mol
First thing I did was calculate how much of C02s weight was carbon. 12.011/31.998= 37.54%
Next what's the carbon weight in one mol of CO2. 44.01x.3754=16.52gr
We know one Briquette is 180 grams so how many mols of CO2 will that make if we are in a perfect world. 180/16.52=10.896mol C02
Now convert that to liters, 10.896x24.465=266.57liters co2
We know 37.54% of Co2 weight is carbon so that means 100-37.54 = 62.46% of CO2 weight is O2
This means 180grams of carbon needs (1.6246x180) 292.428 grams of O2 to become CO2.
292.428g O2 is (292.428/64) 4.57mols which is also (22.4x4.57) 102.35 liters
Air is an avarage of 20.95% Oxygen
This means (100/20.95) 4.77x102.35=488.21liters of air is needed to supply the required oxygen to burn 180 grams of carbon.
My oven is right at 13 liters in size which means one briquette would consume all the oxygen in this oven (488.21/13) over 37.5 times.
Now I could be way off with my numbers, it is late and I just scribbled this all down on a note pad. But it kinda get the idea across, and that is while there is still carbon in the oven our atmosphere will be about 80% nitrogen and 20% CO2. This is assuming we get just CO2 and no C0. One thing we completely forgot to calculate is the expansion of gasses at that temp. This expansion from 68° to 1500° is just under 4 times (3.714) which means we could assume a hot oven would actually need (3.714x488.21) 1,813 liters of air to burn 180gr of carbon. That's a whopping (1813/13) 139.46 times the volume of my oven.