-
The BladeForums.com 2024 Traditional Knife is available! Price is $250 ea (shipped within CONUS).
Order here: https://www.bladeforums.com/help/2024-traditional/
drive belt length for KMG with VFD
- Thread starter melsdad
- Start date
- Joined
- Feb 23, 2007
- Messages
- 132
It depends on the motor mounting location. I use a 27" belt. -Doug
- Joined
- Dec 6, 2010
- Messages
- 1,154
Last edited:
- Joined
- Dec 29, 2005
- Messages
- 1,367
Nope, he means 27"
Mine uses a 24" belt.
Like Doug said, it all depends on the mounting location.
Only the builder, or someone taking measurements from the machine configuration can answer your question Brian.
Mine uses a 24" belt.
Like Doug said, it all depends on the mounting location.
Only the builder, or someone taking measurements from the machine configuration can answer your question Brian.
V-Belt Between Two Pulleys of the Same Diameter
The simplest configuration for a V-belt is a belt stretched between two pulleys that have the same diameter. In this case, the length of the V-belt (L) is (2 x l) + (π x D), where l (lowercase letter L) is the distance between the centers of the two pulleys and D is the diameter of the pulley. The symbol "π" means pi, which equals approximately 3.141593.
V-Belt Between Two Pulleys of Different Diameters
In this case, because the two pulleys have different diameters, the calculation for the V-belt length is more complicated than if the pulleys had the same diameter. Begin with an intermittent calculation of (arcsin(D-d)), where D is the diameter of the larger pulley, and d is the diameter of the smaller pulley. For all trigometric functions in this calculation, use radians for the operation. Divide this result by 2 times l, where l is the distance between the centers of the two pulleys. Label this final result "a."
To calculate the total belt length, use the following formula:
L = (π x (D + d)/2 + 2) x (l x cos(a) + a x (D -- d)/2).
For example, if pulley 1 has a diameter of 4 inches, pulley 2 has a diameter of 3 inches, and the two pulleys are 24 inches apart, then the total belt length is 59 inches.
The simplest configuration for a V-belt is a belt stretched between two pulleys that have the same diameter. In this case, the length of the V-belt (L) is (2 x l) + (π x D), where l (lowercase letter L) is the distance between the centers of the two pulleys and D is the diameter of the pulley. The symbol "π" means pi, which equals approximately 3.141593.
V-Belt Between Two Pulleys of Different Diameters
In this case, because the two pulleys have different diameters, the calculation for the V-belt length is more complicated than if the pulleys had the same diameter. Begin with an intermittent calculation of (arcsin(D-d)), where D is the diameter of the larger pulley, and d is the diameter of the smaller pulley. For all trigometric functions in this calculation, use radians for the operation. Divide this result by 2 times l, where l is the distance between the centers of the two pulleys. Label this final result "a."
To calculate the total belt length, use the following formula:
L = (π x (D + d)/2 + 2) x (l x cos(a) + a x (D -- d)/2).
For example, if pulley 1 has a diameter of 4 inches, pulley 2 has a diameter of 3 inches, and the two pulleys are 24 inches apart, then the total belt length is 59 inches.
- Joined
- Apr 22, 2010
- Messages
- 235
Here's you answer...
http://www.fennerdrives.com/high_performance_composite_vbelts/powertwist_home.aspx
http://www.fennerdrives.com/high_performance_composite_vbelts/powertwist_home.aspx
RyanW
Moderator
- Joined
- Jul 17, 2009
- Messages
- 3,327
That is the correct answer! I have a bunch on the way.
- Joined
- Apr 3, 2008
- Messages
- 522
Thanks for the help guys. I bought a 24" belt on my way home from work, and it worked just fine. I was still flexible with the belt length because I had not drilled the motor mounting holes yet. With my adjustment system a belt from 23"-25" would probably work just fine.