- Joined
- Jan 28, 2008
- Messages
- 133
Hello guys,
I am looking for some advice from someone that has maybe built their own heat treat oven, or knows something about the electrical work involved.
I am currently in the shopping phase of making a heat treat oven from Rashid11's DIY video and google group page. I have decided to make the oven 26.5" x 4" x 4 1/2" inside dimensions instead of his 18" x 4" x 4".
I have found everything I need, k23 bricks from local supplier, K type shielded thermocouple, PID controller, misc wiring elements like ceramic tubes and such for passing element ends through oven wall and a DC input to 220v output 25 amp SSR.
Here is my dilemma, I have everything accounted for but the Kanthal A1 Heating element. I think I have figured out exactly what I need, but I honestly need someone to check my math and my reasoning as I am far from any kind of electrical engineer. Below are my oven specs and the electrical being dedicated to it.
26.5" x 4" x 4 1/2", running off of a 220v 20 amp dedicated circuit. Here is what I am coming up with as far as element needs if I push 17 amps through 17 ga kanthal A1(I have tried and tried to look up ampacity of this kanthal a1 and figure out what the max amp rating is on certain gauge wire but to no avail, Rashid seems to be using 18 gauge and pushing it to 15 amps so i figure 17 amps on 17 gauge should be fine, I WILL find out before making any type of purchase) if anyone knows for sure, please chime in.
OK so with 17 amps using kanthal a1.
220v/17 amps gives me 13 ohms. So to get 13 ohms out of kanthal a1 17 gauge wire rated at .427 ohms per ft. I would need 30.5 ft(366") of wire. If I coil this wire TIGHT with a ID of 5/8 or .625" and the wire itself is .045" diameter I would get a coil approx 26" long minus the 12" of lead I will have for connecting the coil. With this length of coil it will give me an almost perfect 2:1 ratio once stretched to the perimeter of my oven(2:1) I believe 2:1 is what is called for, please correct me if i am wrong the internal perimeter of my oven will be 61".
Here is how I am getting these calculations for length of wire and coil,
length of wire: ohms(13) * ohms per ft rating(.0427) = wire length(30.5')
Lenth of coil: Wire length in Inches(366") / Inside Diameter of coil(.625") * wire gauge(.045") = coil length (26)"
My question after all of this hoopla is, am I thinkin' right, and will this element with 220v - 17 amps get me to temp like I need(FAST) . I know its a lot and I appreciate all the help I can get. Thanks.
I am looking for some advice from someone that has maybe built their own heat treat oven, or knows something about the electrical work involved.
I am currently in the shopping phase of making a heat treat oven from Rashid11's DIY video and google group page. I have decided to make the oven 26.5" x 4" x 4 1/2" inside dimensions instead of his 18" x 4" x 4".
I have found everything I need, k23 bricks from local supplier, K type shielded thermocouple, PID controller, misc wiring elements like ceramic tubes and such for passing element ends through oven wall and a DC input to 220v output 25 amp SSR.
Here is my dilemma, I have everything accounted for but the Kanthal A1 Heating element. I think I have figured out exactly what I need, but I honestly need someone to check my math and my reasoning as I am far from any kind of electrical engineer. Below are my oven specs and the electrical being dedicated to it.
26.5" x 4" x 4 1/2", running off of a 220v 20 amp dedicated circuit. Here is what I am coming up with as far as element needs if I push 17 amps through 17 ga kanthal A1(I have tried and tried to look up ampacity of this kanthal a1 and figure out what the max amp rating is on certain gauge wire but to no avail, Rashid seems to be using 18 gauge and pushing it to 15 amps so i figure 17 amps on 17 gauge should be fine, I WILL find out before making any type of purchase) if anyone knows for sure, please chime in.
OK so with 17 amps using kanthal a1.
220v/17 amps gives me 13 ohms. So to get 13 ohms out of kanthal a1 17 gauge wire rated at .427 ohms per ft. I would need 30.5 ft(366") of wire. If I coil this wire TIGHT with a ID of 5/8 or .625" and the wire itself is .045" diameter I would get a coil approx 26" long minus the 12" of lead I will have for connecting the coil. With this length of coil it will give me an almost perfect 2:1 ratio once stretched to the perimeter of my oven(2:1) I believe 2:1 is what is called for, please correct me if i am wrong the internal perimeter of my oven will be 61".
Here is how I am getting these calculations for length of wire and coil,
length of wire: ohms(13) * ohms per ft rating(.0427) = wire length(30.5')
Lenth of coil: Wire length in Inches(366") / Inside Diameter of coil(.625") * wire gauge(.045") = coil length (26)"
My question after all of this hoopla is, am I thinkin' right, and will this element with 220v - 17 amps get me to temp like I need(FAST) . I know its a lot and I appreciate all the help I can get. Thanks.