Inch/Lbs?

[ThinkOfTheChildren]

The MBC line has a minimum rating of 200 inch/lbs of lock force. Does this mean that my Gunting could take 200lbs of pressure at the tip before lock failure?

The Gunting blade is 3 inches. 3 X 200 = 600. So can my Gunting take 600 pounds of pressure near the pivot before lock failure?

I'm just not sure I understand how to calculate the numbers correctly. Is this right?

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"I can promise you a day of reckoning that you will not live long enough to never forget"

 

[steve22595]

TOTC,

From what I understand, your second calculation is correct. Maybe someone from Spyderco can give the definitive answer.

Steve

 

[bengaiser]

If this torque that we are talking about then the units would be inch*lbs, and not inch/lbs (Torque = Force * Lever Arm).

So, if a knife was rated at 200 inch*lbs, that means the lock can withstand 200 lbs of force 1 inch from the pivot. If the knife were 4 inches long it could withstand 50 (200/4) lbs of force at the tip.

This seems right, but it is 12:30 in the morning so who knows...

Ben

[This message has been edited by bengaiser (edited 02-14-2001).]

 

[Tommi]

Some one beat me in speed... But I will not delete my post.

To make it clear (I might seem meticulous) but lets use right physical quantities to describe lock strenght.
Torgue is force*lever arm, unit is Nm (SI units), the quantity that should be used. One can use mass*lever arm as gravity is pretty much constant in earth thus torgue could be expressed as lbs*inch. The lock is as stong in e.g. moon but lifting 100 lbs mass is a lot easir because of lovere gravity.
Pressure however is force/area of course pressing something is applying force on the target area but there is difference between force and pressure.

But definitely it is lever arms lenght multipied by force (mass if you must) -not divided.

And yes you shoud be able to apply force around pivot pins axis one inch away from the axis that would be enough to lift 600lbs( 0.5 inch from the axis you'd force that would lift 1200lbs). 600lbs*in is about (in SI units) 68 Nm - comparaple to your carengines ability to produce torgue - 2 liter(122 cubic inch) modern engine produces about 180 Nm torgue.

It would be nice if every company used torgue to describe the lock strenght. Spyderco is the only that has done it somehow.

Sorry all - I'll shut up my yacking mode.

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"Good tools to sustain life, or at least make life more convenient"
-James Mattis

[This message has been edited by Tommi (edited 02-14-2001).]

 

[colobbfan]

So, I'm 72 1/2 inches tall and 270 pounds and if I trip and fall on my open knife at the speed of opacity ... I would injure myself on both a three inch bladed knife as well as a four inch long bladed one or for that matter, my cat, who would probably not fare too well either?

Sorry! LOL I'm in a weird mood. Please forgive me...
John

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A day without Spydies is like a day without ... WELL, Spydies!!!

 

[Sal Glesser]

Think. that is correct.

Tommi. these standards that we set up are for our own measurement of Spyderco knives. they are not a "standard" outside of Spyderco. We like to rate the requirements for our own models.

sal