Planning some mods to my Grizzly G1015 but have questions

[Donald Babcock]

Ok, first thing is first. I'm trying to figure some basics out before getting to deep into the planning phases.

The main thing I need help with is as follows (per the manual):

The motor speed is 1725 rpm,arbor size 5/8 inch with a speed of 1750 rpm, and it comes standard with an 8 inch contact/drive wheel, which gives a belt speed of 3600 feet per minute. I'm completly stumped on how to figure out what the belt speed would be with swapping out the 8 inch drive wheel with a standard 4 inch drive wheel. Would the speed be faster or slower with the smaller wheel?

Any help would be appreciated.

 

[Bill DeShivs]

Slower.

 

[TomTheButcher]

I'm thinking it would be twice as fast. Very soon the experts will be piping up with the answer.

 

[12345678910]

A 4 inch wheel is half the speed of the 8 inch wheel

The answer is half,

 

[Donald Babcock]

Thanks, now just need to figure out how to make all the parts that i'll need for the remodel.

 

[sunshadow]

the count is correct. The formula is Drive wheel diameter X pi (3.141592654) X rpm gives you inches per minute (if you measured the diameter in inches) or CM per minute if you measured in CM. To get Feet per minute from your inch based calculations divide your result by 12, to get meters per minute if your measurements were in CM divide by 100. If your wheel you are shopping for is sized in millimeters and you want feet per minute as your final result, multiply the millimeter measurement by 25.4 to convert to inches

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