- Joined
- Feb 2, 2010
- Messages
- 2,138
Okay so I was reading somewhere, I can't remember where, that Michael Janich had said something like, a wharn is a great fighting knife, because it penetrates well. Now I don't care about fighting knives, but I never understood wharncliffs at all. So for the first time since I got my physics degree, I'm gonna actually use what I learned to analyze this: (please excuse my crappy drawing)
So what I have drawn here is the forces that are acting on every point on the edge of the knife that has penetrated into the surface.
The blue indicates my x and y axis.
The red F is the driving force being acted on that point. The F force is broken into two components, in the x direction, and the y direction.
The green is just showing that it is in some sort of material.
The purple is the normal force.
(I left friction out, because they will be equal in both cases, if we assume same surface area, blade width, tip angle, etc)
So on the wharncliff blade, the normal force is pushing on the spine of the blade, EQUAL to the Fy vector, because the spine of the blade has no cutting potential. So the harder you are pushing into the object, the harder the object's normal force is pushing back at you at the spine.
The same forces are present in the "normal blade", but the normal force is dramatically smaller. The edge is "shearing" through the material, and the extremely thin edge has too little surface area for the normal force to act upon. So the Normal force and Fy do NOT cancel each other out, and the remaining force is used to shear the material. In fact, if the knife is very very sharp, Normal force will be almost be zero.
Whereas, with a wharncliff, the normal force on the spine will be the same whether or not the edge is very sharp.
So with equal force, the wharncliff will cancel out some of the power you put into it, and the normal force will redirect your energy DOWNWARD a bit, which is how the edge is able to shear into the material.
Whereas, a normal blade, the cumulative Force vector will be largely unchanged (assuming sharp blade).
I can get if they want a blade with zero belly, but why do people think wharncliffs are "better" for piercing?
So what I have drawn here is the forces that are acting on every point on the edge of the knife that has penetrated into the surface.
The blue indicates my x and y axis.
The red F is the driving force being acted on that point. The F force is broken into two components, in the x direction, and the y direction.
The green is just showing that it is in some sort of material.
The purple is the normal force.
(I left friction out, because they will be equal in both cases, if we assume same surface area, blade width, tip angle, etc)
So on the wharncliff blade, the normal force is pushing on the spine of the blade, EQUAL to the Fy vector, because the spine of the blade has no cutting potential. So the harder you are pushing into the object, the harder the object's normal force is pushing back at you at the spine.
The same forces are present in the "normal blade", but the normal force is dramatically smaller. The edge is "shearing" through the material, and the extremely thin edge has too little surface area for the normal force to act upon. So the Normal force and Fy do NOT cancel each other out, and the remaining force is used to shear the material. In fact, if the knife is very very sharp, Normal force will be almost be zero.
Whereas, with a wharncliff, the normal force on the spine will be the same whether or not the edge is very sharp.
So with equal force, the wharncliff will cancel out some of the power you put into it, and the normal force will redirect your energy DOWNWARD a bit, which is how the edge is able to shear into the material.
Whereas, a normal blade, the cumulative Force vector will be largely unchanged (assuming sharp blade).
I can get if they want a blade with zero belly, but why do people think wharncliffs are "better" for piercing?
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