World Domination

Guyon

Guyon

Biscuit Whisperer
Super Mod
Joined
Mar 15, 2000
Messages
45,835
That's the idea anyway.

Nines_zpsca12cf2c.jpg
 
All are purdy... but I like the second one from the top. De-ramped and o'natural is just sexy.
 
Cue this music.

[video=youtube_share;V92OBNsQgxU]http://youtu.be/V92OBNsQgxU[/video]

I really need five more.
 
I've always liked that higher grind on the cam 9s. Nice little convention. What are you going to use to take over the universe?
 
GarnetandBlack said:
What are you going to do when you run into someone with five 9s? Betcha didn't think about that one, huh?
Click to expand...

I said I needed five more! Nine nines would be the cat's meow. I could bolt them all together and slice watermelons in one swipe.
 
So....I'm guessing you like the BK9.

Ha! Great collection so far. I look forward to seeing all 9.
 
Ah, but what if you could have 9 x 9 of nines? Wouldn't that be da bomb!

Just be careful you don't end up the 8th son of an 8th son of an 8th son, it didn't work out well for Rincewind.
C
-- Wizzard
 
For starters, let's agree that one BK9 (one Becker King) will dominate 9 people.

7.046 billion (divide by) 9 = 782888888.9

You will need 7.829 million Becker Kings to dominate the world.

N=(R)(fp)(ne)(fi)(fc)(L) = by one estimate, 36.4 million (divide by) 9 = 404,444.5

Model our world, you get 7 billion x 404,444.5 = 2.8311 x 10(15)

You'll need 2831111111111111 Becker Kings to dominate the near universe.
 
Guyon cant get the funds together for the stadium rental to photograph all his stoves with his knives....lol
 
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