World Domination

Guyon

Biscuit Whisperer
Super Mod
Joined
Mar 15, 2000
Messages
45,835
That's the idea anyway.

Nines_zpsca12cf2c.jpg
 
All are purdy... but I like the second one from the top. De-ramped and o'natural is just sexy.
 
Cue this music.

[video=youtube_share;V92OBNsQgxU]http://youtu.be/V92OBNsQgxU[/video]

I really need five more.
 
I've always liked that higher grind on the cam 9s. Nice little convention. What are you going to use to take over the universe?
 
What are you going to do when you run into someone with five 9s? Betcha didn't think about that one, huh?

I said I needed five more! Nine nines would be the cat's meow. I could bolt them all together and slice watermelons in one swipe.
 
So....I'm guessing you like the BK9.

Ha! Great collection so far. I look forward to seeing all 9.
 
Ah, but what if you could have 9 x 9 of nines? Wouldn't that be da bomb!

Just be careful you don't end up the 8th son of an 8th son of an 8th son, it didn't work out well for Rincewind.
C
-- Wizzard
 
For starters, let's agree that one BK9 (one Becker King) will dominate 9 people.

7.046 billion (divide by) 9 = 782888888.9

You will need 7.829 million Becker Kings to dominate the world.

N=(R)(fp)(ne)(fi)(fc)(L) = by one estimate, 36.4 million (divide by) 9 = 404,444.5

Model our world, you get 7 billion x 404,444.5 = 2.8311 x 10(15)

You'll need 2831111111111111 Becker Kings to dominate the near universe.
 
Guyon cant get the funds together for the stadium rental to photograph all his stoves with his knives....lol
 
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