I've seen two different kit daggers for sale at the one vendor. One is 7-1/2" OAL with a 3-1/2" long blade. There are 6 pinholes that are 1/8" diameter and (2) 1/4" holes for pins or bolts. The other is 10" overall length, 1/8" thickness with a 4-1/2" blade. It has (2) 3/16" pin holes and one's told to use 3/32" pins.
For a full-tang knife, how does one know how many pins (and corresponding holes to drill) ? Referncing the above, I find it curious that the longer knife would be using smaller dia. pinstock in the one case. Is there a formula of "blade length X then there needs to be Y pin holes ?"
For a full-tang knife, how does one know how many pins (and corresponding holes to drill) ? Referncing the above, I find it curious that the longer knife would be using smaller dia. pinstock in the one case. Is there a formula of "blade length X then there needs to be Y pin holes ?"