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Looks to me that they are say the the lock really did hold under 1000 lbs of load ...
The representative simply doesn't understand what the test measures and how to report it and thus what they are saying is meaningless jibberish. Any folder can take a force of 1000 lbs if you apply it close enough to the pivot and the same folder will fail with a force of 1 lbs if you apply it far enough away from the pivot. Locks of that type will fail under a given torque because you basically have to induce them to rotate to make them break/release. To break a lock by a force you would have to for example pull the blade right out of the handle or drive it back through the handle.
-Cliff
... my understanding of the reply was the the weight was "calculated to be 1000 lbs". That could mean just about any weight at just about any distance from the lock, as long as it calculates out the be 1000 lbs of "lever load".
... the "blade" broke- at the tang in front of the pivot.
Yes, my point was that you can't actually do that calculation. The language isn't correct. As an example, I can give you a bucket and ask you how many rocks it will hold. This question doesn't have an answer because it depends on the size of the rocks. What Benchmade is doing is telling you the bucket holds a lot of rocks which makes you think it is a very big bucket but unless they tell you the size of the rocks you really don't know anything at all.
For example, lets assume that I take a knife which has a failure point of 500 in.lbs on the lock. This means that I can break it with a force of 100 lbs at five inches, 500 lbs at one inch and 10 000 lbs at about 1/16" of an inch. Thus you can't quote a force as a lock strength because it is indeterminate, just like you can't specify the size of a bucket by the amount of rocks it can hold. What most people do is use really small rocks and not tell people just how small the rocks really are. An in.lbs is a really small torque. A normal man can exert about 300 in.lbs for example with just his writs.
Did they mention how much torque was required to do this, it takes a lot to crack off steel through its width like that, even if the width is small. It would be similar to bending a steel through a spine of similar thickness.
-Cliff
That is why I sent them another email asking if it is 1000 foot lbs or 1000 inch lbs ...
Well, in their defense simply numbers are thrown around by a lot of people.
Quote:
Originally Posted by sog View Post
SOG has 1000 lbs of force written down. It is probably inch/pounds. But i can't prove it. Guess you'll have to call them and find out.
"Strength: The Arc-Lock was independently lab tested at over 1000 lbs. of pressure without lock failure."
From :
http://www.sogknives.com/Folding/SpecElite/SE18.htm
Inches per pound would be another insensible unit. Torque is the cross product of force and distance so the units are (force)*(length). In the standard system usually ft.lbs or in.lbs. Lock strengths are always quoted in in.lbs because the numbers would be very lot in ft.lbs and thus not visually impressive. For example 600 in.lbs sounds like a lot, however 50 ft.lbs does not. They are however both the same number.
-Cliff