Mete please explain

Joined
Feb 17, 2007
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From another thread I did want to confuse LOL. I am curious though.

Ms[F] = 930 - 600x % C - 60x % Mn -50 x% Cr -30 x % Ni -20x % Si -20 x % Mo -20 x % W It's all just a numbers game !!

This is the formula for Ms? If I take those numbers and plug in my steel specs and I should come out with the correct MS?

1095 .95c x 600 = 570 then 930-570 = 360f simple but, Metalurgy Fundementals shows over 400f

51200 1c x 600 = 600 + .36Mn x 50 = 18 + 1.4Cr x 30 = 42 + .2Ni = 4 for total of 664 and 930-664 = 266f Nope

So are the MN and CR and Ni minus for a minus 64 on those and a plus 600 for the C to get 930-536 for a Ms of 394f
neither seem right by my book what am I doing wrong
Thanks jim
 
Timken formulas are in the "Practical Data for Metallurgists" You can find it online at www.timken.com , check ' Knowledge Center' , 'For Engineers' .....I hadn't used that formula for a long time. One of the problems of formulas, diagrams etc is that they are using one specific steel chemistry and doing it under laboratory conditions. Yet each steel is melted to a range for each element .If you picked the low range for each vs the high range for each there would be quite a difference ! I worked it out for average 52100 chemistry and it was very different from that listed .My book is the eighth edition , the online one is the fifteenth edition .This latest one actually has three listings for 52100 data. That will confuse people !!...In any case understand where the data comes from and that it's not an absolute.[ I hope Tai Goo doesn't read this !]
 
Don't worry Mete. I didn't read a thing. :D
the3monkeys.jpg
 
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