Here are two setups:
A)
3500rpm 2 pole motor direct drive turning a 4" drive wheel.
B)
1750rpm 4 pole motor belt driven with 4" driving pulley and 2" driven pulley on a shaft turning a 4" drive wheel. For simplicity and for theoretical physics discussions purposes only, suppose belt slippage does NOT occur.
Here is my understanding, please correct me if i am wrong.
The motor in A has half the torque of motor B. However, motor B is transferring half of its original torque to the driven pulley, and therefore the drive wheel. So the torque at the drive wheel is the same for both A and B. Also, the drive wheels in both A and B have the same 3500rpm. So on paper, the performance of these two are the same.
C)
1750rpm 4 pole motor belt driven with a 2"-3"-4" stepped driving pulley and a 2" driven pulley on a shaft turning a 4" drive wheel.
D)
2500rpm dc motor belt driven with a 3" driving pulley and a 2" driven pulley on a shaft turning a 4" drive wheel. Suppose there is a speed controller with a range 50%-100% of max speed, which with the pulley ratio is close to the speed range of C, let us just say it is exactly the same for simplicity.
Again, my understanding is as follows.
The speed of the drive wheel is roughly the same at corresponding speed settings of C and D (using 2" step in C corresponds to min speed on dc controller in D, using 4" step in C corresponds to max speed in D). D has constant torque at all speeds, but can only transfer 2/3 of the torque to the drive wheel. For C, with 2" step the full torque of the motor is transferred to the drive wheel, and with 4" step only half the torque is transfered to the drive wheel. So at min speed D is easier to stall, and at max speed C is easier to stall. When using the 3" step, C is just as easy to stall as D.
I would like to make a similar comparison with VFDs, but i dont really understand all the various VFD settings. Is there some interesting dynamic like with C and D above?
A)
3500rpm 2 pole motor direct drive turning a 4" drive wheel.
B)
1750rpm 4 pole motor belt driven with 4" driving pulley and 2" driven pulley on a shaft turning a 4" drive wheel. For simplicity and for theoretical physics discussions purposes only, suppose belt slippage does NOT occur.
Here is my understanding, please correct me if i am wrong.
The motor in A has half the torque of motor B. However, motor B is transferring half of its original torque to the driven pulley, and therefore the drive wheel. So the torque at the drive wheel is the same for both A and B. Also, the drive wheels in both A and B have the same 3500rpm. So on paper, the performance of these two are the same.
C)
1750rpm 4 pole motor belt driven with a 2"-3"-4" stepped driving pulley and a 2" driven pulley on a shaft turning a 4" drive wheel.
D)
2500rpm dc motor belt driven with a 3" driving pulley and a 2" driven pulley on a shaft turning a 4" drive wheel. Suppose there is a speed controller with a range 50%-100% of max speed, which with the pulley ratio is close to the speed range of C, let us just say it is exactly the same for simplicity.
Again, my understanding is as follows.
The speed of the drive wheel is roughly the same at corresponding speed settings of C and D (using 2" step in C corresponds to min speed on dc controller in D, using 4" step in C corresponds to max speed in D). D has constant torque at all speeds, but can only transfer 2/3 of the torque to the drive wheel. For C, with 2" step the full torque of the motor is transferred to the drive wheel, and with 4" step only half the torque is transfered to the drive wheel. So at min speed D is easier to stall, and at max speed C is easier to stall. When using the 3" step, C is just as easy to stall as D.
I would like to make a similar comparison with VFDs, but i dont really understand all the various VFD settings. Is there some interesting dynamic like with C and D above?