Iron carbides are relatively not as hard as compared to the other four, and they sum up to about .8% too depending on the batch for example vanadium carbide is a 9.5 on the mohs scale with diamond being 10 and hardened steel comes at around (...)
Be careful with this statement, since it's not true in a general sense.
When you have a structure made up of hard particles embedded in a much softer matrix, there are two independent wear mechanisms: pure abrasion, and tear-out.
The first will only be significant if: a) The percentage of hard particles is high enough to provide a reasonable cover of matrix, and b) The abrading material is also stiff with respect to the matrix (non conforming). The second part is significant in metal working tools, but not in food,wood or manila rope cutting.
When the dominant mechanism for wear is tear-out, the hardness of the particles (as long as they are much harder than the matrix) does not matter. The difference in hardness between iron carbide and vanadium carbide is not consequential.
Two characteristics of the carbides that do matter are percentage, and size. More carbides provide better coverage of the matrix, minimizing tear out. Smaller carbides provide a better hold onto the matrix due to the smaller volume/surface ratio. For practical reasons, it's not possible to get both this characteristics with highly soluble carbides, and steels with a good carbide volume will have other carbide formers in them.