Now, this is just one more step into this discussion of the liner lock. The force applies to the liner, which can affect how tough the liner has to be. AGAIN, this is NOT a DISCOVERY, it's just another factor the knife makers must know already, I am just talking this out and see if anyone is interested to look at it.
Below are simplified diagrams of the blade in BROAD SIDE VIEW with sharp edge on the LEFT and the spine of the blade on the right as shown in (d).
painfull poetry
If you look at drawing
(d), you see the blade that is anchor at the
PIVOT point "
O". You see the liner in(
GREEN) that prevent the blade from rotating
COUNTER CLOCKWISE. The length of the blade from tip to PIVOT "
O" has length of "
L". The length from "
O" to the farthest point of the liner is "
R" shown.
In drawing
(e), I show only the force and length to simplify. You see the
APPLY FORCE "
F" to the tip of the blade
90deg to the blade shown to attempt to rotate the blade in
counter clockwise direction shown in dotted arrow. The force "
T" is right angle to "
R" as shown. Just simple physics
T=F X
(L/R). This mean for blade length
L, the shorter
R is, the more rotation force experience on the liner.
In drawing
(f), I further separate the "
T" into downward force "
V" and horizontal force in
GREEN ( which I don't care for now). I call angle show "
Theta". You can see the downward force
V = T cos(Theta). Therefore
V=F x
(L/R) cos(Theta).
Meaning the stress on the liner depends on the blade length
L vs
R, and less obvious but just as or more importantly, depends on angle
Theta.
Again, I did
NOT discover anything here, just reverse engineering what the knife designer and get a better feeling what to look out. The designer had to consider this already. These are VERY SIMPLE STUFFS. Just something to talk about if anyone is interested in this.