I am a stock removal guy working mostly with ATS34. However, I just made my first knife from 1095 and thought about doing a differential quench on it out of the furnace. Couldn't bring myself to do it. I am not being a smart ass but what is the purpose of this treatment? I am using a steel with spring properties so it should stand up to excessive bending. Along with other tests, I did put the knife in a vice and bent it about 5 degrees with a nice spring back. I didn't put a pipe over the handle and apply 250 pounds of force (can you imagine the sharp steel flying around the shop if that came loose?) And why would someone want to do that with a knife anyway????
Yes, your steel has "spring properties" but ONLY if tempered that way! Once you take a steel to full hard, it's just that - HARD! Now, to take advantage of the "spring properties" you need to draw it back/temper it accordingly.
One of the best known spring steels is 5160. Bring it up to austenizing temp and quench it in brine! Full hard! It'll shatter like glass. Yet, you might say, "I thought it had "spring properties!" True, but "spring" qualities come from high tempering temperatures AFTER martensite formation.
That's when you get a "REAL" spring.
If you hardened your 1095, you DON'T have a spring anymore. You'll need to draw back the spine to get some "spring properties".
The differential heat treatment would be recommended for a large knife that may end up getting camp-type abuse of cutting saplings for firewood. You may want the blade to "give" a little over its long length before it would break.
This treatment can be accomplished in numerous ways.
In some arenas, this is proof that the maker can selectively control the hardening of his blade, thus showing experience and knowledge.