- Joined
- Apr 13, 2016
- Messages
- 199
I recently downloaded an app that has almost every blade steel known to man, listed with properties and a brief description and/or comparison to other, typically American, steels.
Anyway, I point this out because I've come across what I would consider something that makes no sense to me when trying to study 9Cr18MoV. I had thought it was reasonably similar to 440C, in use and application. But this application I've been using says the following about the 9Cr18 line...
9Cr18: Chinese stainless alloy, similar to AISI 440C stainless steel. Most notable difference being the absence of Molybdenum from it's composition. Obviously that is detrimental to it's performance as a knife steel, Mo is a strong carbide former, not the best, but still better than nothing.
From this I take that 9Cr18 alone, before any MoV, is closest matched to 440C. It says that the lack of Mo alone is a negative thing, determent as they claim. So I assume that the addition of the Mo should then take it a grade above standard 9Cr18. Right?
9Cr18Mo: Chinese equivalent of 440C stainless steel.
Okay, I'm a little confused, but maybe I read wrong. I thought the addition of Mo was not just a positive thing, but a very positive thing, given the lack thereof was considered detrimental. But maybe they embellished just how negative a lack of Mo really is. Okay I'll let it slide, however...
9Cr18MoV: Chinese equivalent of 440B steel. Slightly better performer due to increased amounts of Molybdenum in it's composition, and addition very small amounts of Vanadium. ~0.10% of Vanadium will not affect steel wear resistance in any meaningful way, however it does have positive affect on grain refinement, which is always desirable.
Okay, so now I'm thoroughly confused. They very clearly state that both Molybdenum and Vanadium are positive additions to a steels composition, yet when they're added to the standard 9Cr18, which is apparently most comparable to 440C, they suddenly make 9Cr18MoV more comparable to the lower grade 440B???
Any help here? Am I wrong in my thinking that 440B is lower grade than 440C? If not, then why is it that the addition of better, more strengthening materials to 9Cr18, renders it a weaker, lesser version?
Anyway, I point this out because I've come across what I would consider something that makes no sense to me when trying to study 9Cr18MoV. I had thought it was reasonably similar to 440C, in use and application. But this application I've been using says the following about the 9Cr18 line...
9Cr18: Chinese stainless alloy, similar to AISI 440C stainless steel. Most notable difference being the absence of Molybdenum from it's composition. Obviously that is detrimental to it's performance as a knife steel, Mo is a strong carbide former, not the best, but still better than nothing.
From this I take that 9Cr18 alone, before any MoV, is closest matched to 440C. It says that the lack of Mo alone is a negative thing, determent as they claim. So I assume that the addition of the Mo should then take it a grade above standard 9Cr18. Right?
9Cr18Mo: Chinese equivalent of 440C stainless steel.
Okay, I'm a little confused, but maybe I read wrong. I thought the addition of Mo was not just a positive thing, but a very positive thing, given the lack thereof was considered detrimental. But maybe they embellished just how negative a lack of Mo really is. Okay I'll let it slide, however...
9Cr18MoV: Chinese equivalent of 440B steel. Slightly better performer due to increased amounts of Molybdenum in it's composition, and addition very small amounts of Vanadium. ~0.10% of Vanadium will not affect steel wear resistance in any meaningful way, however it does have positive affect on grain refinement, which is always desirable.
Okay, so now I'm thoroughly confused. They very clearly state that both Molybdenum and Vanadium are positive additions to a steels composition, yet when they're added to the standard 9Cr18, which is apparently most comparable to 440C, they suddenly make 9Cr18MoV more comparable to the lower grade 440B???
Any help here? Am I wrong in my thinking that 440B is lower grade than 440C? If not, then why is it that the addition of better, more strengthening materials to 9Cr18, renders it a weaker, lesser version?