Grains, Carbides, and You

First, and this is a common thing so don't take it personally, the FCC structure doesn't have molecules. It is made of individual atoms stacked over and over, but they are generally all of one type of atom, in this case iron. These stacks are not perfect, and sometimes there is a missing iron atom. It can either stay empty, which isn't of much interest for knife steels, or it can be filled with another element, such as Mn, Cr, or others. These are still just stacked atoms, and are not bonded the way molecules are.

The grain structure isn't a larger structure. The austenite has it's own grains and structures. They look just like the ones in the 1095, but they are austenite, while the 1095 in the picture is pearlite. (They don't look exactly the same, but the differences aren't relevant at this point.) In 1095, and in steels in general with more than 0.8% carbon, there will be some carbides in the austenite too. This combined mixture is what I'd call the grain structure. If you ask for grain size, you are asking for the specific average size of the grains individual grains themselves. If you ask for carbide size, you are asking for the average size of the individual carbides.
Thank you so much. I won't take anyone helping me to understand personally ever.

I was confusing irons crystaline matrix, body centered, or face centered with iron molecules. I have seen iron molecules represented in that body centered pattern but never mind, that doesn't matter for what I'm trying to grasp.

This video which was presented as a choice by youtube after I watched yours really helped me to grasp the relation of grain structure to irons crystaline structure (epiphany starts at about 30 seconds in).

[video=youtube;uh4obOPltpw]https://www.youtube.com/watch?v=uh4obOPltpw[/video]
So the carbon is trapped in solution with irons crystaline structure and those crystals form a grain structure between crystals as they form. Now, how are the carbides brought into the mix? Do they only form at the grain boundary or are they trapped within the crystaline structure itself as well?

Thanks for being patient.
 
Something to bear in mind is that all the things we discuss are steel specific. For instance CPM D2 looks different from the picture above. The grains are roughly the same size, the carbide volume is similar, but the carbides are smaller, and the center region with no carbide wouldn't be there. What someone might think of as an exception might more accurately be described as a specific trait..


Your comment on CPM-D2 is relevant.

Though the volumes are the same, the structure is totally different.

Making CPM-D2 behave much differently then regular D2, both in both fabrication and use.


The composition might be the same, but the potential of the CPM steel, when treated correctly, is improved in both grain and carbide structure.


A win-win situation for both the maker and end-user (except for the price), and making the comparison of the two steel more difficult.



Big Mike
 
What still confuses me is the grain refinement of the various forms of producing steel. Traditional D2, for example, has coarse carbides that make edge refinement difficult, reduce blade toughness and increase edge wear resistance. That’s ingot D2, one of the most popular and respected of the traditional knife steels.

The apex of a sharp knife edge is 1 to 2 microns wide. The carbides in D2 are 40 microns or so. A traditional steel like 12C27, Sandvik’s main knife steel, will have an average carbide size of 0.5 micron. The large D2 carbides are not evenly distributed. They can clump, reducing toughness. And they can rip out when the steel is sharpened. You can literally put a razor’s edge on 12C27.

My unsupported understanding is that the average grain size in D2 was about 10 microns, with the grain size of powder D2(CPM D2) being 5 microns. I realize that Me2 disagrees, saying the powder process has little effect on grain size, but neither of us has been able to present any evidence. I don't care who is right, I'd just like to know.

But we seem to agree that the carbides will be smaller and more uniformly distributed in powder D2 than in ingot D2, making the powder steel tougher and better able to be honed to a fine edge.

Now comes PSF27, which is Carpenter’s D2 made with the spray forming process. The alloy is the same as D2, but the spray forming process is supposed to create a “very fine grain,” reduce carbide size, improve carbide distribution, increase toughness and allow the blade to be hardened to a higher Rc. In other words, the steel will have much better edge stability (strength and toughness) and be able to sharpened to a finer edge. It's D2 on steroids.

But what happens to the grain structure?
 
Wow, I always thought I knew so much about steels, but boy was I wrong! Hey, at least I know a lot more after this thread. This has urged me to head to the library and get some books on metallurgy and material science!

Me2, thanks so much for sharing this! This should be a sticky, everyone comes in the forums acting like they're a metallurgist, yet I doubt they know any of the info stated in here. It should be a requirement to read this thread once you join BF.

Thanks again!:thumbup:
 
Twindog , part of the confusion is that people are rather casual about terms .Grains are grains an carbides are carbides , don't mix the two !
A typical knife steel has both carbides and martensite in in it's structure .In HT we have those two things to control. Deal with the carbide size and distribution first , then deal with th grain size. We want small carbide size and small grain size .Both have benefits.
 
Dave you like to see molecules in the steel ! Metals have metallic bonding, molecules have molecular bonding . To throw in some more confusion --carbides sometimes have metallic bonding , sometimes molecular bonding , and sometimes BOTH !!
Metallic bonding gives us crystals .Metallurgists can deal with that ! Molecular bonding is weird to metallurgists ! They take a string with random direction to the string axis or they can align the molecular chains with the string axis and get very high strength !!
 
Your comment on CPM-D2 is relevant.

Though the volumes are the same, the structure is totally different.

Making CPM-D2 behave much differently then regular D2, both in both fabrication and use.


The composition might be the same, but the potential of the CPM steel, when treated correctly, is improved in both grain and carbide structure.


A win-win situation for both the maker and end-user (except for the price), and making the comparison of the two steel more difficult.



Big Mike

Do you have any micrographs of CPM D2? How is the grain structure improved? Finer, more uniform? Other? The carbide size is smaller and more evenly distributed. Its not that I disagree with Twindog, I just haven't seen anything showing the grains to be that fine. I'd love to see the information on D2 with an average grain size of 10 um and powder D2 of 5 um. Grain size and carbide size are wholly dependent on processing. Even with austenization temperatures near 2300 degrees F, high speed steels have average grain sizes of 5-6 um when processed properly. Break a HSS end mill and look at how fine the structure is. I'm sure D2 can reach that size, but the processing is very specific and generally can't be done by knife makers, though some are capable should they choose to do so. I do have some micrographs of S110V, and the grains are in the 25-40 micron range. I believe it was Twindog who referenced some material from Carpenter on the final powder particle size using their process (I don't like the "generation" labels, as they imply a superiority that might not be there in terms of final product). The powder size was ~150 um or 0.006" in diameter. Any of the grain sizes we've discussed here are much smaller, about 1/5 or less. So, powder size has an influence most likely, but with grains reforming with each heat cycle, its probably not the primary factor.

FWIW, I've seen sharpened knife edges that were probably down to 0.5 microns, and some people go even beyond that.

Very Fine Grain has a specific definition, if one chooses to use it that way. It's defined as an ASTM grain size between 10 and 12.
 
So the carbon is trapped in solution with irons crystaline structure and those crystals form a grain structure between crystals as they form. Now, how are the carbides brought into the mix? Do they only form at the grain boundary or are they trapped within the crystaline structure itself as well?

Thanks for being patient.

This is where it gets a little tricky. As in the video, room temperature steel in the annealed condition has ferrite, right? Ferrite holds basically no carbon at room temperature. So where does it go? It goes into carbides!! This will probably throw a lot of people, but annealed steel has more carbide than hardened steel. As the steel cools, any carbon that cannot be dissolved into the iron around it will combine with iron and bond with it (metallically or otherwise, as pointed out by mete), and iron bonded with carbon is iron carbide AKA Fe3C AKA cementite. When steel is heated above the austenization temperature, the austenite will dissolve MUCH more carbon than ferrite. The carbides start to shrink, some disappear, and that carbon goes into the austenite, gets trapped by the quench, and forms martensite, with some carbide left over, distributed based on prior heat treatment procedures. These are referred to as undissolved carbides, for reasons above. Now, again as seen in the video, cementite will be present in austenite at carbon contents above 0.8%. Steels with less than 0.8% carbon will not have carbides left when heated to hardening temperatures. Remember though that even 1018 steel has carbides in the annealed condition at room temperature, they just all dissolve into the austenite above about 1330 deg F. Below is a video I made a while back. Some might find it useful, though it's not intended specifically for this discussion.

https://www.youtube.com/watch?v=lOJHrkh__SQ
 
What still confuses me is the grain refinement of the various forms of producing steel. Traditional D2, for example, has coarse carbides that make edge refinement difficult, reduce blade toughness and increase edge wear resistance. That’s ingot D2, one of the most popular and respected of the traditional knife steels.

The apex of a sharp knife edge is 1 to 2 microns wide. The carbides in D2 are 40 microns or so. A traditional steel like 12C27, Sandvik’s main knife steel, will have an average carbide size of 0.5 micron. The large D2 carbides are not evenly distributed. They can clump, reducing toughness. And they can rip out when the steel is sharpened. You can literally put a razor’s edge on 12C27.

My unsupported understanding is that the average grain size in D2 was about 10 microns, with the grain size of powder D2(CPM D2) being 5 microns. I realize that Me2 disagrees, saying the powder process has little effect on grain size, but neither of us has been able to present any evidence. I don't care who is right, I'd just like to know.

But we seem to agree that the carbides will be smaller and more uniformly distributed in powder D2 than in ingot D2, making the powder steel tougher and better able to be honed to a fine edge.

Now comes PSF27, which is Carpenter’s D2 made with the spray forming process. The alloy is the same as D2, but the spray forming process is supposed to create a “very fine grain,” reduce carbide size, improve carbide distribution, increase toughness and allow the blade to be hardened to a higher Rc. In other words, the steel will have much better edge stability (strength and toughness) and be able to sharpened to a finer edge. It's D2 on steroids.

But what happens to the grain structure?

You can "literally" put a razors edge on ingot D2 as well.

Please, folk, read back: having large carbides at the edge allows for MORE edge-refinement, and not just a little bit more but 10-100X more refinement. With its small carbides and volume, you can sharpen 12C27 down to 0.5 um apex diameter ... but you can achieve 0.05 - 0.005 um with WC-Co, diamond, and obsidian, i.e. carbide edges. Why? Because the carbides are harder (> 80Rc), less flexible or prone to deformation, so they can be shaped to a point/plane 10-100X narrower than low carbide 12C27 can achieve with any stability. 12C27 taken that sharp is LESS stable (strength & toughness) because it is too soft to resist deformation at such thin geometry, it rolls and flattens. If you could place ingot D2's large carbides in the apex and shape them appropriately, you'd have a knife 10-100X sharper in that section. If D2 is "toothy" at a microscopic level, it is from having some sections of sharper carbide (much sharper than 12C27 anywhere) and some sections of duller matrix ("dull" at 0.5 um like 12C27).

With 12C27 and other razor steels, they easily take a "dull" edge, but that edge (0.5um) is "shaving sharp" and relatively "tough" against impact stress meaning it with deform rather than fracture - lots of room on the stress/strain curve. With harder carbide, there isn't much room in the stress/strain curve for deformation hence it being "brittle" not in the sense that it is weak, indeed it is much stronger than the matrix, stronger than 12C27 at max hardness, especially at such thin geometries where it will actually hold its shape, but in the sense that when lateral or impact stress is applied it will NOT deform as readily and will fracture in short order. That said, it isn't usually the carbide itself fracturing but rather the weak bond with the matrix (grain boundary).

To improve steel toughness, industry works to reduce the size of these carbide-grain boundaries by reducing the size of the carbides themselves such that lateral and impact stress on a section of edge can be distributed to many small grain-boundaries rather than one large one more susceptible to fracture-growth.

But again, the 12C27 and other"fine" steels do not obtain a "finer edge" than others, they simply are able to obtain that "fine edge" (more of a weak "working edge" really) more easily than high-carbide materials, and that edge is tougher and easier to maintain (requires less careful technique, less specialized equipment).

When speaking in relative terms - fine, dull, tough, brittle, strong, weak - it is important to specify the measurement range you are describing. If comparing >80Rc to ~60Rc, which is weak? If comparing 0.5um to 0.05um, which is "fine" or "sharp" vs. "dull"?
Also, when discussing "edge stability", one should specify the geometries (edge thickness) and stress to which that geometry is subjected. Remember that abrasive wear is, at the microscopic level, impact stress and lateral loading, so an edge more resistant to that stress could be described as "more stable" ... but the conditions are very specific.



If someone understands these notions differently, please explain why as i am by no means an expert. Alright, now back to an awesome thread about the matrix grain size (rather than carbide grain size). Thank you for your patience.
 
Do you have any micrographs of CPM D2? How is the grain structure improved? Finer, more uniform? Other? The carbide size is smaller and more evenly distributed. Its not that I disagree with Twindog, I just haven't seen anything showing the grains to be that fine...


I have no evidence of smaller grain size in the CPM-D2.

I believe the difference in the behavior of CPM-D2 compared to D2 when it comes to grinding/sharpening is the more even distribution of the smaller carbides.

I don't believe the more uniform grain structure of the CPM steel adds much to the ease of grinding/sharpening. Though I can see where it, combined with the smaller carbides, could result in a steel less likely to fracture at the carbide boundaries when stressed.



Big Mike
 
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I have no evidence of smaller grain size in the CPM-D2.

I believe the difference in the behavior of CPM-D2 compared to D2 when it comes to grinding/sharpening is the more even distribution of the smaller carbides.

I don't believe the more uniform grain structure of the CPM steel adds much to the ease of grinding/sharpening. Though I can see where it, combined with the smaller carbides, could result in a steel less likely to fracture at the carbide boundaries when stressed.
Big Mike


As Me2 just said, the size and distribution of carbides is important, but for the same reasons, nonmetallic inclusions (impurities) are equally or more important, depending on the way the steel was processed.

Carbide size is especially important to a steel’s toughness, its ability to avoid chipping. Both carbides and nonmetallic inclusions (impurities) act as stress risers, making the steel more likely to chip on impact stress. Large carbides, especially when clumped, are more powerful stress risers. Smaller carbides, more uniformly distributed, improve steel toughness.

In a conventionally produced steel like ingot D2, the carbides are large — 35 to 50 microns. Non-metalic inclusions are about the same size and both act similarly as defects in the steel, reducing toughness and increasing the steel’s vulnerability to chipping.

With the powder processing, the carbides are made smaller and better distributed. PM carbides are about 2 to 4 microns, while the inclusions are 5-15 microns. PM steel is tougher because of these smaller carbides, but the larger nonmetallic inclusions become the weak link more than carbides because of their larger size. In other words, PM steel is tougher than its ingot counterpart, but not as tough as it could be because of the size of inclusions.

This finding brought about the need for cleaner second and third generation PM steels, which reduce nonmetallic inclusions and further improve the impact resistance of steel.

http://www.bucorp.com/files/Stamping_Journal_3G_PM_Steel.pdf
 
You can "literally" put a razors edge on ingot D2 as well.

Please, folk, read back: having large carbides at the edge allows for MORE edge-refinement, and not just a little bit more but 10-100X more refinement. With its small carbides and volume, you can sharpen 12C27 down to 0.5 um apex diameter ... but you can achieve 0.05 - 0.005 um with WC-Co, diamond, and obsidian, i.e. carbide edges. Why? Because the carbides are harder (> 80Rc), less flexible or prone to deformation, so they can be shaped to a point/plane 10-100X narrower than low carbide 12C27 can achieve with any stability. 12C27 taken that sharp is LESS stable (strength & toughness) because it is too soft to resist deformation at such thin geometry, it rolls and flattens. If you could place ingot D2's large carbides in the apex and shape them appropriately, you'd have a knife 10-100X sharper in that section. If D2 is "toothy" at a microscopic level, it is from having some sections of sharper carbide (much sharper than 12C27 anywhere) and some sections of duller matrix ("dull" at 0.5 um like 12C27).

With 12C27 and other razor steels, they easily take a "dull" edge, but that edge (0.5um) is "shaving sharp" and relatively "tough" against impact stress meaning it with deform rather than fracture - lots of room on the stress/strain curve. With harder carbide, there isn't much room in the stress/strain curve for deformation hence it being "brittle" not in the sense that it is weak, indeed it is much stronger than the matrix, stronger than 12C27 at max hardness, especially at such thin geometries where it will actually hold its shape, but in the sense that when lateral or impact stress is applied it will NOT deform as readily and will fracture in short order. That said, it isn't usually the carbide itself fracturing but rather the weak bond with the matrix (grain boundary).

To improve steel toughness, industry works to reduce the size of these carbide-grain boundaries by reducing the size of the carbides themselves such that lateral and impact stress on a section of edge can be distributed to many small grain-boundaries rather than one large one more susceptible to fracture-growth.

But again, the 12C27 and other"fine" steels do not obtain a "finer edge" than others, they simply are able to obtain that "fine edge" (more of a weak "working edge" really) more easily than high-carbide materials, and that edge is tougher and easier to maintain (requires less careful technique, less specialized equipment).

When speaking in relative terms - fine, dull, tough, brittle, strong, weak - it is important to specify the measurement range you are describing. If comparing >80Rc to ~60Rc, which is weak? If comparing 0.5um to 0.05um, which is "fine" or "sharp" vs. "dull"?
Also, when discussing "edge stability", one should specify the geometries (edge thickness) and stress to which that geometry is subjected. Remember that abrasive wear is, at the microscopic level, impact stress and lateral loading, so an edge more resistant to that stress could be described as "more stable" ... but the conditions are very specific.



If someone understands these notions differently, please explain why as i am by no means an expert. Alright, now back to an awesome thread about the matrix grain size (rather than carbide grain size). Thank you for your patience.



Carbides may be able to be sharpened to a high degree, but that is a difficult process. And with large carbides, you're left with large, weak carbide-grain/carbide-carbide boundaries that increase the likelihood of chipping. Razor edges, with their acute geometry, have to be tough.
 
Carbides may be able to be sharpened to a high degree, but that is a difficult process. And with large carbides, you're left with large, weak carbide-grain/carbide-carbide boundaries that increase the likelihood of chipping. Razor edges, with their acute geometry, have to be tough.

That depends on use. Razor-edges, with their acute geometry, have to be strong first, i.e. able to hold that narrow apex with minimal support during use. Again, the low-carbide steel razor blade is only ~0.5um apex diameter, i.e. it is blunt beyond that diameter. If that blade were sharpened to 15-DPS from the apex back, understand that a carbide-apex, able to achieve 10-100X thinner apex diameter, extends 20-200X beyond that steel apex, in this case 1-10 microns further. When you are talking about a fragile edge and comparing the two, remember that in regard to how much more material support the steel has vs the carbide. The steel is already blunt, its edge has already been lost, and only back that full 1-10 microns from the apex does it achieve a useful "stability".

Also keep in mind that razor-blades and scalpels are not intended for impact or lots of lateral stress. When subjected to such use, the carbide edge fractures due to low ductility while the steel edge bends/flexes/deforms. Steel's toughness and ease of manufacture/maintenance is the reason it is selected for such tools where such stresses may occur and where that extra 10-100X sharpness is not required. 0.5 um is plenty sharp for most knife tasks anyway, and the wear-resistance offered by large carbides is not as important for a lot of knife tasks.

To Big Mike, studies of carbide-size have demonstrated that smaller carbides are easier to grind away with high grit (fine abrasives) compared to large carbides which strongly resist such grinding. However, with low grit coarse abrasives, the abrasives impact the large inflexible carbides and fracture them out of the matrix, resulting in lower wear-resistance but greater ease of manufacture at that grit. So grinding CPM-D2 with fine abrasives (e.g. >600 grit) should be easier than grinding ingot D2, but the reverse is true for grinding each with 200 grit.
 
According to Crucible: The uniform distribution of fine carbides also prevents grain growth, so that the resultant microstructure is fine grained.

http://www.crucibleservice.com/eselector/general/generalpart3.html

So would that not imply that the CPM D2, with its more uniform distribution of fine carbides, is more likely to have a finer grain structure than ingot D2?


This issue may also relate to Chiral's discussion of razor edges needed high strength. Strength is a function of hardness, and the powder and spray forming processes, with their finer and better distributed carbides, are able to achieve higher hardness.
 
I think you might be reading quite generic material too closely. Ingot D2 has very fine carbides as well, there are just fewer of them.

Chiral, how are those other materials sharpened?
 
With large carbides the fractures travel from carbide to carbide.With small carbides that's usually not true. => tougher !
 
According to Crucible: The uniform distribution of fine carbides also prevents grain growth, so that the resultant microstructure is fine grained.

http://www.crucibleservice.com/eselector/general/generalpart3.html

So would that not imply that the CPM D2, with its more uniform distribution of fine carbides, is more likely to have a finer grain structure than ingot D2?


This issue may also relate to Chiral's discussion of razor edges needed high strength. Strength is a function of hardness, and the powder and spray forming processes, with their finer and better distributed carbides, are able to achieve higher hardness.

:thumbup: I'd be interested to hear more about how the PM process retards grain-growth. I'd read that vanadium and other alloys aid in that, but I am not a metallurgist so do not really understand the processes at work. Regarding increased hardness from finer, better distributed carbides, that may be so for steels, it is certainly so for hardmetals like WC-Co.

I think you might be reading quite generic material too closely. Ingot D2 has very fine carbides as well, there are just fewer of them.

Chiral, how are those other materials sharpened?

Tungsten-carbide can be abraded (wet-grinder) with SiC or Diamond abrasive. Actual "diamond blades" for diatomes... I have no idea. Obsidian blades are shaped via precise conchoidal fracturing. Neither of the latter are all that practical except for VERY specific applications, but tungsten-carbide technology continues to improve with stronger, tougher tools:
http://www.cartech.com/techarticles.aspx?id=1620
http://www.allaboutcementedcarbide.com/
http://www2.sandvik.com/sandvik/0130/HI/SE03411.nsf/2d2e706ae473b93dc1256b5600446430/651f6e334db04c46c125707600562c88/$FILE/Cemented%20Carbide.pdf

With large carbides the fractures travel from carbide to carbide.With small carbides that's usually not true. => tougher !

Indeed, but i think it has more to do with the "binder" than the carbides. With small, diffuse carbides, there is more binder between carbides to absorb the stress. You may still have multiple little fractures that simply cannot reach one another, but it may take more energy to start each of those fractures. With larger carbides at the same volume%, you have far fewer grain-to-carbide boundaries but there is less "binder" around each carbide (surface area : volume) to absorb the stress, so carbides fracture-out more easily and it is more obvious when they do. However, I would like to read the study showing the propensity for carbide-to-carbide fracture progression as it relates to carbide size vs volume. In 94% carbide hardmetals (very brittle), carbide-to-carbide fracture progresses more easily (i.e. requires less force) to travel between smaller carbide-grains, it is a more linear path, vs. traveling around one large carbide to get to another. As a result, hardmetals with larger carbides present an average higher toughness than the same with smaller carbides. However, the difference between the two is miniscule. Tungsten-carbide materials are generally so brittle, they register single-digits on Charpy V-notch tests if any value at all, so the preference is to rely on slow-load "fracture toughness" tests.
 
This is where it gets a little tricky. As in the video, room temperature steel in the annealed condition has ferrite, right? Ferrite holds basically no carbon at room temperature. So where does it go? It goes into carbides!! This will probably throw a lot of people, but annealed steel has more carbide than hardened steel. As the steel cools, any carbon that cannot be dissolved into the iron around it will combine with iron and bond with it (metallically or otherwise, as pointed out by mete), and iron bonded with carbon is iron carbide AKA Fe3C AKA cementite. When steel is heated above the austenization temperature, the austenite will dissolve MUCH more carbon than ferrite. The carbides start to shrink, some disappear, and that carbon goes into the austenite, gets trapped by the quench, and forms martensite, with some carbide left over, distributed based on prior heat treatment procedures. These are referred to as undissolved carbides, for reasons above. Now, again as seen in the video, cementite will be present in austenite at carbon contents above 0.8%. Steels with less than 0.8% carbon will not have carbides left when heated to hardening temperatures. Remember though that even 1018 steel has carbides in the annealed condition at room temperature, they just all dissolve into the austenite above about 1330 deg F. Below is a video I made a while back. Some might find it useful, though it's not intended specifically for this discussion.

https://www.youtube.com/watch?v=lOJHrkh__SQ
So I'm assuming that when Chromium or Vanadium is in the mix that the excess carbon forms carbides with that instead. I'm still trying to understand where and how the carbides are distributed and held. I know the carbon is trapped "in solution" by the quench between the bonds of the iron atoms. Where are the undissolved carbides? Are they only at grain boundaries or in the grains themselves as well. You say "distributed based on prior heat treatment procedures". I'm trying to absorb basic concepts from this thread. Kind of a general idea of how things usually go to get a better working understanding.

Does small carbides (only) = smaller grain structure?

Interesting subject.
 
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