chiral.grolim
Universal Kydex Sheath Extension
- Joined
- Dec 2, 2008
- Messages
- 6,422
Isn't this pretty much what I stated?
At low pressure they are fairly close though the coarse still has advantage. In order to drive the coarse abrasive further into the steel more force needs to be applied. Yes the fine abrasive fails to deliver even with more force and presumably a like increase in depth or even greater as a percentage of its total size (proportionately, it cannot dig deeper than it stands proud), but I never claimed otherwise. Added depth per pass = greater stock removal for a similar feed rate, it requires additional force for the coarse abrasive to distinguish itself.
The 80% figure - 80% of a 20 micron abrasive depth is 16 micron. 80% of a 100 micron potential depth is...80 microns. Again, these are random assignments - actual abrasive depth is a fraction of these numbers in most cases. In many cases with a coarse abrasive it is probably not possible to drive the abrasive to 80% depth with anything approaching normal operating pressures. Not needed in any event, 50% in this example is still 50 micron, far more than the 20 micron depth of the smaller abrasive.
I just want to be sure that we are on the same page. :thumbup:
Using "% depth" as a measure of anything is not likely to be helpful. Consider the distance of the binder-surface from the work-piece as you attempt to reach this % depth, or how much work-piece material must be displaced to achieve it. Remember, the abrasive particles do not exist in isolation, they are surrounded by their compatriots all pursuing the same depth (well, not all, we know that no hone is engineered with perfect uniformity of grit size among the abrasive particles, but you get the idea), and they are also surrounded by the space between each particle. In the fine grit (your 20 micron example), there are MANY many more particles pushing in and, conversely, holding back the hone from reaching the desired level of penetration. THAT is why it takes so much more force to get the same level of wear-performance (measured by amount of material removed from the work-piece) with the fine-grit vs the coarse-grit.
Look at the chart presented:
It takes 2 kgf for the (presumably) 15 um abrasive to achieve the same rate of wear as the 30 um abrasive achieves with only 1 kgf. And at 4kgf on the 15 um abrasive you have not been able to meet the performance of the 30 um abrasive using only 2 kgf. It is possible that using even more force with the high-grit/low-micron hone will cease to present improvements in performance as it "bottoms out" while the low-grit/high-micron hone continues to perform until eventually it too "bottoms out".
Recognize that the reason that the hones have roughly equal performance at the low-force levels is that the low-grit/high-micron teeth are already penetrating deeper than the high-grit/low-micron teeth. If it were otherwise, there is no way low-grit could match high-grit due to the massive difference in the number of teeth making contact. The highest-grit hone always has the highest number of teeth making contact. If the high and low grits were penetrating to the same depth (not % depth) at a given force level, the high-grit would win out because of number of teeth alone. But that is not what is observed! Both the 1979 and 1999 papers show equal performance for low and high grits at low pressure when clearing is efficient. The low-grit should be at a disadvantage due to fewer teeth working, but the fewer teeth allow for deeper penetration at a given level of force = more material removed per tooth which compensates for the reduced arsenal and more than compensates as more pressure is applied.
In other words, it is possible that the force required to achieve "80% depth" or whatever fraction you choose is the same regardless of grit size.